Question

a flat rectangular piece of aluminum has a perimeter of 64 inches. the length is 10 inches longer than the width. find the width

Answer 1

Answer:

The width of the piece is 11 inches

Step-by-step explanation:

Let

x ----> the length of the rectangular piece of aluminum in inches

y ----> the width of the rectangular piece of aluminum in inches

we know that

The perimeter of the rectangular piece of aluminum is equal to

$P=2(x+y)$

we have

$P=64\ in$

so

$64=2(x+y)$

simplify

$32=x+y$ ----> equation A

$x=y+10$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$32=y+10+y$

solve for y

$32=2y+10$

$2y=32-10$

$2y=22$

$y=11$

therefore

The width of the piece is 11 inches