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Salim wants to survey the students at his middle school about how much time they spend on homework. he will interview a sample o

Aloiza [94]

Using sampling concepts, it is found that the method that would result in a random sample is given by:

Pick 150 students' names from a jar that has the names of all the students in the school.

<h3>How are samples classified?</h3>

Samples may be classified as:

Convenient: Drawn from a conveniently available pool.

Random: All the options into a hat and drawn some of them.

Systematic: Every kth element is taken.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.

Researching the problem on the internet, the representative(all possible students can possibly be sampled) and random sample is given by the following option:

Pick 150 students' names from a jar that has the names of all the students in the school.

More can be learned about sampling concepts at brainly.com/question/25122507

#SPJ1

8 0

2 years ago

What is 4.4E-10 divided by 5.5E17

notsponge [240]

my answer is 8e-28

your welcome.

6 0

3 years ago

Henrique drew and labeled the net shown. He also labeled the areas of the left and right triangular sides.

Oksana_A [137]

Answer: $SA=117.2\ in^2$

Step-by-step explanation:

You need to remember the following:

1. The area of a rectangle can be calculated with the following formula:

$A_r=lw$

Where "l" is the length and "w" is the width.

2. The area of a triangle can be calculated with the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

Use those formulas to find the area of each face.

<u> Area of the rectangle</u>

$A_r=(10\ in)(4\ in)=40\ in^2$

<u>Area of two triangles</u>

There are two equal triangles. Each one has a base of 10 inches and a height of 5 inches. Then, their areas are equal:

$A_{t1}=A_{t2}=\frac{(10\ in)(5\ in)}{2}=25\ in^2$

The areas of the other two triangles (which are equal) are:

$A_{t3}=A_{t4}=13.6\ in^2$

Adding the areas of the faces, you get that the surface area of the rectangular pyramid is:

$SA=40\ in^2+25\ in^2+25\ in^2+13.6\ in^2+13.6\ in^2\\\\SA=117.2\ in^2$

3 0

3 years ago

Read 2 more answers

A matinee movie ticket costs $6.50 per child. Which equation can be used to calculate the matinee ticket price, M, for n childre

zloy xaker [14]

Answer:

M = 6.50n

Step-by-step explanation:

since it is per child, it will be multiplied by the amount of children, n. Therefore giving us the cost of M, or the equivalent.

5 0

3 years ago

Read 2 more answers

A pilot flies on a bearing of 160° for 30 miles. The pilot then executes a quick turn and flies another 15 miles at a bearing of

vivado [14]

Answer: 34.65 miles at an angle of 325.39°

Step-by-step explanation:

Ok, the initial position is (0,0)

Then she flies 30 miles at an angle of 160°, if we count the angle counterclokwise from the x-axis, the new position will be:

p = (30*cos(120°), 30*sin(120°))

Then she travels another 15 miles at an angle of 205°, the new position is:

p = (30*cos(120°) + 15*cos(205°), 30*sin(120°) + 15*sin(205°))

p = (-28.59 , 19.64)

If she now travles X miles at an angle Y, we must have that the final position is the point (0,0)

this means that:

X*cos(Y) = -(-28.59) = 28.59

X*sin(Y) = -19.64

Now, we can find the quotient between those two equations and use that tan(x) = sin(x)/cos(x)

X*(sin(Y))/(X*cos(Y)) = -19.64/28.59

Tg(Y) = -0.69

Y = ATg(-0.69) = -34.61°

If we use only positive angles, this angle is equivalent to:

360° - 34.61° = 325.39°

now lets find the distance:

Xcos(325.39°) = 28.59

X = 28.59/cos(325.39°) = 34.65 miles.

4 0

3 years ago