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The equation of the line is, .
Given that,
The equation of the line is,
And contains the point (-2, -5).
We have to determine,
What is the equation of the line that is perpendicular to the given line?
According to the question,
The equation of the line is,
On comparing with the standard equation of the line y = mx +c.
The slope of the line is 1/3.
When two lines are perpendicular the relation between these slopes is,
And line contains the point (-2, -5).
Then,
Therefore,
The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,
Hence, The required equation of the line is, .
For more details refer to the link given below.
Answer:
c)
Step-by-step explanation:
−2 = −⅔[5] + b
−3⅓
1⅓ = b
y = −⅔x + 1⅓
Then convert to Standard Form:
y = −⅔x + 1⅓
+⅔x + ⅔x
__________
⅔x + y = 1⅓ [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
3[⅔x + y = 1⅓]
* 1⅓ = 4⁄3
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