Sent a picture of the solution to the problem (s).
If you are talking about the binomial being expanded then it would be:
8x^3 + 12x^2y + 6xy^2 + y^3
The y in the second term is not part of the exponent
And since you are raising the binomial to the third, you would be using the third row of Pascal's triangle.
Hope this helped!
Substitute this into the parabolic equation,
We're told the line 
intersects 
twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know
We can tell from the quadratic equation that has its vertex at the point (3, 6). Also, note that
and
so the furthest to the right that extends is the point (5, 2). The line passes through this point for 
. For any value of 
, the line passes through either only once, or not at all.
So 
; in set notation,
