Answer:
![a \: b \: d \: f \\ mathematical \: sentence \: is \: one \: \\ which \: has \: a \: sign \: like = < \: \: \: \: \: \\ > \: \: \: \: \: \leqslant \: \: \: \: \: \geqslant](https://tex.z-dn.net/?f=a%20%5C%3A%20b%20%5C%3A%20d%20%5C%3A%20f%20%5C%5C%20mathematical%20%5C%3A%20sentence%20%5C%3A%20is%20%5C%3A%20one%20%5C%3A%20%20%5C%5C%20which%20%5C%3A%20has%20%5C%3A%20a%20%5C%3A%20sign%20%5C%3A%20like%20%3D%20%20%3C%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%5C%20%20%20%20%3E%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Cleqslant%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Cgeqslant%20)
it must always have one of the sign
You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
![k=\dfrac{m}{5}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7Bm%7D%7B5%7D)
Step-by-step explanation:
Let Kat reads k pages of the book.
Miguel reads 5 times as many pages of the book as Kat. So,
m = 5k ...(1)
Together they read 54 pages. i.e.
m+k = 54 ...(2)
From equation (1),
![k=\dfrac{m}5{}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7Bm%7D5%7B%7D)
Hence, the equation that can be used to find how many pages Kat read is equal to
.
The common ratio is the multiplication of 2 each time. 5x2= 10// 10x2=20// 20x2=40