Answer:
t = 0.53 hr
Step-by-step explanation:
We write expressions for the distances walked by these two people, sum them up and set the sum equal to 4 miles:
(3.5 mph)(t) + (4mph)(t) = 4 mi
Combining these terms:
(7.5 mph)(t) = 4 mi
4 mi
Solving for t: t = ---------------- = 0.53 hr
7.5 mph
Answer:
y = -1/2 x
Step-by-step explanation:
Option B is the correct answer.
Answer:
4,000
Step-by-step explanation:
you take this years total (2683)
and add how many more there was last year (1317)
then you get 4000!!
hope it helps
Answer:
A. tan(x) = 2.4/10
Step-by-step explanation:
The question is incomplete and lacks the required diagram. Find the question and diagram attached below.
Which equation can be used to solve for the measure of angle ABC? tan(x) = 2.4/10 tan(x) =10/2.4 sin(x) =10/10.3 sin(x) =10.3/10
We will use the SOH CAH TOA identity to calculate the equation needed to solve for angle ABC.
In a right angled triangle, the side facing the acute angle ABC is the opposite, the longest side is the hypotenuse and the third side (base) is the adjacent.
From the diagram shown;
AB = hypotenuse = 10.3cm
AC = opposite = 2.4cm
BC = adjacent = 10cm
To get the angle x, we can use the SOH and TOA identity.
SOH means sin<ABC = opp/hyp
Sin(x) = AC/AB = 2.4/10.3
TOA ≈ Tan(x) = opp/adj
Tan(x) = 2.4/10
The equation that can be used to solve for the measure of angle ABC are therefore sin(x) = 2.4/10.3 OR tan(x) = 2.4/10
Based on the given option,
tan(x) = 2.4/10 is the only correct answer.
Answer: (a) 0.344578
(b) 0.211855
Step-by-step explanation: Let X represent Jill's score and Let Y represent Jack's score.
Jill's scores are approximately normally distributed with mean 170 and standard deviation 20 implies :
X ≈(170 , )
Also , since Jack's scores are approximately normally distributed with mean 160 and standard deviation, it implies
Y ≈ ( 160 , ).
It is given that their scores are independent which means that the outcome one one will not affect the outcome of the other, we the have:
Y - X ≈ N(-10 ,+ )
Y - X ≈ N(-10 ,625 )
Also , Y + X ≈ N ( 330 , 625 )
(a) We need to find the approximate probability that Jack's score is higher , that is
P ( Y > X)
=P(Y - X >0)
= P ( >
= 1 - Ф()
= 1 - Ф()
= 1 - Ф ( 0.4)
= 1 - 0.655422
= 0.344578
P ( Y > X) ≈ 0.345
(b) We need to calculate the approximate probability that their total score is above 350 , that is
P ( X + Y > 350)
= P ( > )
= 1 - Ф()
= 1 - Ф ( 0.8)
= 1 - 0.788145
= 0.211855
P ( X + Y > 350)≈ 0.212