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3 years ago

Find quotient and remainder b)diving 2x^3- 5x² +x+2

Mathematics

1 answer:

tekilochka [14]3 years ago

3 0

Given:

Dividend = $2x^3-5x^2+x+2$

Divisor = $x-2$

To find:

The quotient and remainder.

Solution:

We have,

Dividend = $2x^3-5x^2+x+2$

Divisor = $x-2$

Divide $2x^3-5x^2+x+2$ by $x-2$ as shown in the below picture.

Dividing $2x^3-5x^2+x+2$ by $x-2$ , we get

$Quotient=2x^2-x-1$

$Remainder=0$

Therefore, $Quotient=2x^2-x-1$ and $Remainder=0$ .

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Find the coordinates of P ' if D o, 2.4 (x,y) is applied to the triangle below

guajiro [1.7K]

Answer:

The coordinates of P' are (4.8,-4.8).

Step-by-step explanation:

The rule of dilation $D_{o,2.4}(x,y)$ represent the dilation with scale factor 2.4 and center at origin.

If the scale factor of the dilation is k and the center is (0,0), then

$(x,y)\rightarrow (kx,ky)$

Since the scale factor is 2.4, therefore

$(x,y)\rightarrow (2.4x,2.4y)$

From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are

$P(2,-2)\rightarrow P'(2.4(2),2.4(-2))$

$P(2,-2)\rightarrow P'(4.8,-4.8)$

Therefore the coordinates of P' are (4.8,-4.8).

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3 years ago

Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The

pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that $p = 0.905$

You and 2 friends:

So 3 people in total, which means that $n = 3$

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412$

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009$

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245$

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

With what we found in b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991$

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

$p = 0.905*0.095*0.095 = 0.0082$

0.0082 = 0.82% probability that only your order will be filled correctly

7 0

3 years ago

Find the maximum production level p = 100x^{0.34}y^{0.66} if the total cost of labor (at $72 per unit) and capital (at $40 per u

Anton [14]

Maximum production p=552728

Step-by-step explanation:

The equation for maximum production is : $p=100x^{0.34} y^{0.66}$

The number of units of labor is x @$72

The number of units of capital is y @$40

The total cost of labor and capital is limited to $270,000, this can be written as;

72x+40y ≤ $270,000

Graphing the inequality to find values of x and y ,from the graph;

x=3750 units

y=6750 units

Applying the expression for maximum production

$p=100*x^{0.34}* y^{0.66} \\\\p=100*3750^{0.34} *6750^{0.66} \\\\p=552727.56\\\\p=552728$

Learn More

Inequalities graphs :brainly.com/question/11386040

Keywords: maximum, production,cost, labor,limited to,capital ,unit

#LearnwithBrainly

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2 years ago

What is the length of segment A (2,1) B (6,6)

stepladder [879]

4.7 because if you plug it in- (2,1) and (6,6) it is 4.7 units

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3 years ago

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Ludmilka [50]

The solution of your problem is shown on the picture below.

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2 years ago