Question

Find quotient and remainder b)diving 2x^3- 5x² +x+2

Answer 1

Given:

Dividend = $2x^3-5x^2+x+2$

Divisor = $x-2$

To find:

The quotient and remainder.

Solution:

We have,

Dividend = $2x^3-5x^2+x+2$

Divisor = $x-2$

Divide $2x^3-5x^2+x+2$ by $x-2$ as shown in the below picture.

Dividing $2x^3-5x^2+x+2$ by $x-2$, we get

$Quotient=2x^2-x-1$

$Remainder=0$

Therefore, $Quotient=2x^2-x-1$ and $Remainder=0$.