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kotykmax [81]
3 years ago
10

Suppose the point (2, 4) is on the graph of y = f(x). Find a point on the graph of the given function.

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

we are given the function y = f(x) in which the point (2,4) is present. This means the coordinate of the function y = f(x + 1) is still 4 while the x in the first function is added with one. Therefore, the answer to this problem is option C (3,5)
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9) The original price of a coffee table is d dollars. You use a coupon and buy the table for (d - 4)
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Step-by-step explanation:

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Marcus randomly draws tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green
IrinaVladis [17]

Answer: 1. D) 30

2. A) 8

3. B) 4/15

4. A)  2/9

5.D) 64%

Step-by-step explanation:    

1. Since, here the tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token.

Thus, the total token = 10 blue tokens+ 8 green tokens+ 12 red tokens = 30 token

Therefore, If the first draw is a green token, Then total outcomes that will possible = 30.

2. Since, getting green is an event with 8 favorable outcomes.

Therefore,  If the first draw is a green token, Then total favorable outcomes that will possible = 8.

3. The possibility of getting green in first drawn, P(G) = \frac{8_C_1}{30_C_1}

P(G) =  \frac{8}{30} = \frac{4}{15}

4. Here, Number of red socks= 5

Number of white socks = 2 and Number of  blue socks=3

Therefore total socks = 10

⇒ Probability of picking a pair of red socks,

P(R)= \frac{5_C_2}{10_C_2} = \frac{10}{45}

⇒ P(R)= 2/9

5. Since, here coin is flipped 50 times and lands on heads 32 times.

Therefore, experimental probability that coin will land on heads on the next flip = (total times in which head appears/ total number of experiments) × 100 = (32/50)×100=64%


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3 years ago
4.82 <br> write as a fraction or mixed number in simplest form
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2 years ago
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
3 years ago
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