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lorasvet [3.4K]
4 years ago
8

Jacie can swim 3/4 of a mile in 3/8 of an hour.how far can she swim in one hour?

Mathematics
1 answer:
Vladimir [108]4 years ago
8 0

Answer:

2 miles

Step-by-step explanation:

convert 3/4 into 6/8. With this you have a ratio of 6/8 miles to 3/8 hours. Meaning 2/8 mile is equal to 1/8 of an hour. With this you can find that Jacie can swim 2 miles in a hour



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In triangle opq right angled at p op=7cm,oq-pq=1 determine the values of sinq and cosq
soldi70 [24.7K]

Answer:

see explanation

Step-by-step explanation:

let pq = x

given oq - pq = 1 then oq = 1 + x

Using Pythagoras' identity, then

(oq)² = 7² + x²

(1 + x)² = 49 + x² ( expand left side )

1 + 2x + x² = 49 + x² ( subtract 1 from both sides )

2x + x² = 48 + x² ( subtract x² from both sides )

2x = 48 ( divide both sides by 2 )

x = 24 ⇒ pq = 24

and oq = 1 + x = 1 + 24 = 25 ← hypotenuse

sinq = \frac{opposite}{hypotenuse} = \frac{7}{25}

cosq = \frac{adjacent}{hypotenuse} = \frac{24}{25}



6 0
4 years ago
Can you write a real world problem that uses Pythagorean theorem ?
elena-14-01-66 [18.8K]

1) Road Trip: Let’s say two friends are meeting at a playground. Mary is already at the park but her friend Bob needs to get there taking the shortest path possible. Bob has two way he can go - he can follow the roads getting to the park - first heading south 3 miles, then heading west four miles. The total distance covered following the roads will be 7 miles. The other way he can get there is by cutting through some open fields and walk directly to the park. If we apply Pythagoras's theorem to calculate the distance you will get:

(3)<span>2 </span>+ (4)2 =

9 + 16 = C2

√25 = C

5 Miles. = C

Walking through the field will be 2 miles shorter than walking along the roads. .

2) Painting on a Wall: Painters use ladders to paint on high buildings and often use the help of Pythagoras' theorem to complete their work. The painter needs to determine how tall a ladder needs to be in order to safely place the base away from the wall so it won't tip over. In this case the ladder itself will be the hypotenuse. Take for example a painter who has to paint a wall which is about 3 m high. The painter has to put the base of the ladder 2 m away from the wall to ensure it won't tip. What will be the length of the ladder required by the painter to complete his work? You can calculate it using Pythagoras' theorem:

(5)<span>2 </span>+ (2)2 =

25 + 4 = C2

√100 = C

5.3 m. = C

Thus, the painter will need a ladder about 5 meters high.

3) Buying a Suitcase: Mr. Harry wants to purchase a suitcase. The shopkeeper tells Mr. Harry that he has a 30 inch of suitcase available at present and the height of the suitcase is 18 inches. Calculate the actual length of the suitcase for Mr. Harry using Pythagoras' theorem. It is calculated this way:

(18)<span>2 </span>+ (b)2 = (30)2

324 + b2 = 900

B2 = 900 – 324

b= √576

= 24 inches

6 0
3 years ago
Someone pls pls pls help me outt i have 3 questions left
adoni [48]

why do u cheat in exams lol

5 0
3 years ago
Celinda thought of 89.5 in parts, 80 + 9 + 0.5, and divided each part: 80 ÷ 10 = 8; 9 ÷ 10 = or 0.9; 0.5 ÷ 10 = 0.05. Then she a
Arlecino [84]

Answer:

Dividing each part into 10 and then summing the results up, is equivalent to dividing 89.5 into 10.  

Step-by-step explanation:

This example refers to the Distributive Property of the division, which is valid when the dividend is decomposed.

A simple example could be: 400 ÷ 10 = (200 ÷ 10) + (200 ÷ 10)

In the exposed example we know that 89.5 = 80 + 9 + 0.5.

  • <u>Option 1</u>

(80/10) + (9/10) + (0.5/10) =

8 + 0.9 + 0.05=

8.95

  • <u>Option 2</u>

89.5/10 = 8.95

     

8 0
3 years ago
Ana escribe conjuntos de cinco enteros positivos consecutivos con la siguiente propiedad: La suma de tres de los números es tan
Keith_Richards [23]

Answer:

a) 1.

Step-by-step explanation:

Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.

Luego, el conjunto de los cinco enteros positivos se puede expresar como

A = {a; a+1; a+2; a+3; a+4}

Dada la condición del problema, se debe cumplir que

a + (a+1) + (a+2) = (a+3) + (a+4)

⇒  3a + 3 = 2a + 7

Resolviendo la ecuación resulta

a = 4

Luego, el conjunto A nos resulta

A = {4; 5; 6; 7; 8}

Puede concluirse que sólo un conjunto cumple con esta condición.

5 0
3 years ago
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