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Flura [38]
3 years ago
8

G(n) = 4n+1 h(n)= -2n+3 Find (g+h)(n)

Mathematics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

14 - 4n

Step-by-step explanation:

g = 4n+1/n

n = 1/g−4

---------------------------------------

h = −2n+3/n

n = 3/h+2

---------------------------------------

g(- n + 3) = 4(- n + 3) + 2 = - 4n + 12 + 2 = 14 - 4n

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7<br> 9<br> 3<br> 10<br> Simplify the answer if possible.)
Brilliant_brown [7]

i don't really get what the question  is could you write it again?

4 0
3 years ago
What is the answer to -t+9-4t=59?
kkurt [141]

Answer:

-10

Step-by-step explanation:

combine like terms -5x+9=59 subtract 9 from both side and get -5x=50 so x=-10

3 0
3 years ago
Read 2 more answers
NEED HELP ASAP Need someone to explain how to do this
DIA [1.3K]

Answer:

Oh cool! The answer is 90 since a and c or parallel, b cuts through them perpendicularly, forming a right angle.

Step-by-step explanation:

6 0
3 years ago
For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?
STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

z=\frac{x-\mu}{\sigma}

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of -0.25.

Upon substituting our given values in z-score formula, we will get:

-0.25=\frac{x-500}{100}

-0.25*100=\frac{x-500}{100}*100

-25=x-500

-25+500=x-500+500

x=475

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0
3 years ago
URGET PLEASE HELP QUICKLY
alexdok [17]

Answer: -0.5.

Step-by-step explanation:

The constant of variation k for the direct variation is given by:-

k= \dfrac{f(x_2)}{x_2}=\dfrac{f(x_1)}{x_1}

The given table:

x  f( x )

0   0

2   -1

4    -2

7   -3.5

Then,

k=\dfrac{-1}{2}=\dfrac{-2}{4}=\dfrac{7}{-3.5}=-0.5

Hence, the constant of variation k for the direct variation is -0.5.

4 0
3 years ago
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