The correct answer is solve for y in the second equation.
Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. ...
Step 2: Subtract the second equation from the first.
Step 3: Solve this new equation for y.
Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.
Answer:
Regular Polygons
Polygons can also be classified as equilateral, equiangular, or both. Equilateral polygons have congruent sides, like a rhombus. Equiangular polygons have congruent interior angles, like a rectangle. When a polygon is both equilateral and equiangular, it is called a regular polygon.
So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=<span>2x+8+x
</span>Simplifying process:
<span><span><span>3x</span>+</span>−5</span>=<span><span><span>2x</span>+8</span>+<span>x
</span></span><span>Combine Like Terms </span>⇒ 3x−5=<span>(2x+x)+(8)
</span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span>Second thing we are now going to do is s<span>ubtract 3x from both sides<span> so:
</span></span><span><span><span>3x</span>−5</span>−<span>3x</span></span>=<span><span><span>3x</span>+8</span>−<span>3<span>x
</span></span></span><span>−5</span>=<span>8
</span>Final step is to add 5 to both sides:
−5+5=<span>8+5
</span>0=<span>13
</span>The answer to your question is "<span>There are no solutions"</span>
Answer: {(x + 2), (x - 1), (x - 3)}
Step-by-step explanation:
Presented symbolically, we have:
x^3 - 2x^2 - 5x + 6
Synthetic division is very useful for determining roots of polynomials. Once we have roots, we can easily write the corresponding factors.
Write out possible factors of 6: {±1, ±2, ±3, ±6}
Let's determine whether or not -2 is a root. Set up synthetic division as follows:
-2 / 1 -2 -5 6
-2 8 -6
-----------------------
1 -4 3 0
since the remainder is zero, we know for sure that -2 is a root and (x + 2) is a factor of the given polynomial. The coefficients of the product of the remaining two factors are {1, -4, 3}. This trinomial factors easily into {(x -1), (x - 3)}.
Thus, the three factors of the given polynomial are {(x + 2), (x - 1), (x - 3)}
