To separate hard candie and marbles what is the efficient method

A sample of impure tin of mass 0.526 g is dissolved in strong acid to give a solution of Sn2 . The solution is then titrated wit

SVEN [57.7K]

Answer:

55.7%

Explanation:

The reaction that takes place is:

3Sn²⁺ + 2NO₃⁻ + 8H⁺ → 2NO + 3Sn⁺⁴ + 4H₂O

With the volume and concentration of NO₃⁻ solution, we can calculate the moles of Sn²⁺ that reacted:

3.67x10⁻² L * 0.0448 M = 1.64x10⁻³ mol NO₃⁻

1.64x10⁻³ mol NO₃⁻ * $\frac{3molSn^{2+}}{2molNO_{3}^{-}}$ = 2.47x10⁻³mol Sn²⁺

Now we convert moles of Sn to mass, using its atomic weight:

2.47x10⁻³mol Sn²⁺ * 118.71 g/mol = 0.293 g Sn

Finally we calculate the percent by mass of Sn:

0.293 g / 0.526 g * 100% = 55.7%

4 0

4 years ago

How would you dispose the following waste materials

ELEN [110]

To dispose natural waste :

insted of wasting this natural waste u can use them as fertilizer to the plants

To dispose plastic waste : 

recycling , reuse and reduce is the process

hey ya mate !!

hope it helps!! (ʘᴗʘ✿)

8 0

3 years ago

Can you identify a sample from a living organism by examining it under a microscope? Yes or No

Ghella [55]

Vguttfvjhhutdxcbhyyyhhhhhhh HD jv bc HD g G G HD F G G f ft

6 0

3 years ago

For each of the following pairs of substances, determine which has the larger molar entropy at 298 K: (A) Br₂(l) or (B) Cl₂(g) (

irakobra [83]

Explanation:

Entropy is defined as the degree of randomness present in a substance. Therefore, more is the irregularity present in a compound more will be its molar entropy.

Hence, decreasing order to molar entropy in state of matter is as follows.

Gases > Liquids > Solids

In the first pair, we are given $Br_{2}(l)$ or $Cl_{2}(g)$ . Since, molar entropy of liquids is less than the molar entropy of gases.

Hence, $Cl_{2}(g)$ will have larger molar entropy as compared to $Br_{2}(l)$ .

In the second pair, we are given Fe(s) or Ni(s). More is the molar mass of a compound more will its molar entropy. Molar mass of Fe is 55.84 g/mol and molar mass of Ni is 58.69 g/mol.

Hence, molar entropy of Ni(s) is more than the molar entropy of Fe(s).

In the third pair, we are given $C_{2}H_{6}(g)$ or $C_{2}H_{4}(g)$ . As both the given species are gaseous in nature. So, more is the molar mass of specie more will be its molar entropy.

Molar mass of $C_{2}H_{6}(g)$ is 30.07 g/mol and molar mass of $C_{2}H_{4}(g)$ is 28.05 g/mol. Therefore, molar entropy of $C_{2}H_{6}(g)$ is more than the molar entropy of $C_{2}H_{4}(g)$ .

In the fourth pair, we are given $CCl_{4}(g)$ or $CH_{4}(g)$ . Molar mass of $CCl_{4}(g)$ is 153.82 g/mol and molar mass of $CH_{4}(g)$ is 16.04 g/mol.

Therefore, molar entropy of $CCl_{4}(g)$ is more than the molar entropy of $CH_{4}(g)$ .

In the fifth pair, we are given HgO(s) or MgO(s). Molar mass of HgO is 216.59 g/mol and molar mass of MgO is 40.30 g/mol.

Hence, molar entropy of HgO(s) is more than the molar entropy of MgO.

In the fifth pair, we are given NaCl(aq) or $MgCl_{2}(aq)$ . Molar mass of NaCl 58.44 g/mol and molar mass of $MgCl_{2}(aq)$ is 95.21 g/mol.

Hence, the molar entropy of $MgCl_{2}(aq)$ is more than the molar entropy of NaCl(aq).

5 0

3 years ago

Liquid hydrogen boils at -252°C. What is the boiling point on the Kelvin scale?

DaniilM [7]

Answer:

Boiling point in kelvin is 373.1 \

boiling point of liquid hydrogen in kelvin is 21.15

Explanation:

5 0

3 years ago