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icang [17]
2 years ago
14

How does the volume occupied by a cubic centimeter compare with the volume occupied by a millimeter

Chemistry
1 answer:
Bad White [126]2 years ago
7 0
I'm pretty sure it's the same 2mm = 2cc = 2c^2
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The temperature of 300 milliliters of a gas at 400K is increased to 800K, pressure remaining constant. What will the new volume
Annette [7]

Answer:

V₂ = 600 mL

Explanation:

Given data:

Initial volume = 300 mL

Initial temperature = 400 K

Final temperature = 800 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 300 mL × 800 K / 400 k

V₂ = 240000 mL.K / 400  K

V₂ = 600 mL

4 0
2 years ago
Explain why gases such as the oxygen found in tanks used as hospitals are compressed. why must care be taken to prevent compress
allochka39001 [22]

They are compressed so that a larger amount of gas can be stored in a smaller container. A greater mass confined to a smaller volume makes transporting and storing of gases easier. Increasing temperature increases pressure, and the cylinders might explode. Before compressed oxygen can be breathed, it must be decompressed.

7 0
3 years ago
Read 2 more answers
3. Dorji was provided with four colourless solutions. He was asked to
givi [52]

Answer:

First, we can test Solution 1. We know that Sodium Hydroxide is a strong base. If we test acids on blue litmus paper, they will turn red. If we test bases on red litmus paper, they will turn blue.  So, you can test all the of the solutions- water, sodium hydroxide and hydrochloric acid with blue and red litmus paper. HCl, Hydrochloric acid is an acid, so it will turn blue litmus paper red. It will not turn red litmus blue. The acids will turn blue litmus paper red. The bases will turn red litmus paper blue. Only water is a neutral liquid, which will not turn blue litmus paper red or red litmus paper blue. It will not change the colour of it. Thus, if you test all the solutions with blue and red litmus paper, you will know which solution is water.  Water is the only one which is neutral. It is the only solution which cannot change the colour of any litmus paper. Thus, you can identify it very easily.  

5 0
3 years ago
Balance the combustion eqation; __C5H + __O2 ---> __CO2+__H2O
stira [4]
This equation C5H + O2 ---> CO2 + H2O has a mistake.

C5H is wrong. You missed the subscript of H.

I will do it for you assuming some subscript to show you the procedure, but you have to use the right equation to get the right balanced equation.

Assuming the tha combustion equation is C5H12 + O2 ---> CO2 + H2O

First you need to  balance C, so you put a 5 before CO2 and get

C5H12 + O2 ---> 5CO2 + H2O

Now you count the hydrogens: 12 on the left and 2 on the right. So put a 6 before H2O and get:

C5H12 + O2 ---> 5CO2 + 6H2O

Now count the oxygens: 2 on the left and 16 on the right, so put an 8 on before O2:

=> C5H12 + 8O2 ---> 5CO2 + 6H2O.

You can verify that the equation is balanced
8 0
2 years ago
Calcula el pH de las siguientes sustancias formadas durante una erupción volcánica:
Virty [35]

<em>Calculate the pH of the following substances formed during a volcanic eruption: </em>

<em>• Acid rain if the [H +] is 1.9 x 10-5 </em>

<em>• Sulfurous acid if [H +] = 0.10 </em>

<em>• Nitric acid if [H +] = 0.11</em>

<em />

<h3>Further explanation  </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

  • pH acid rain

\tt pH=-log[1.9\times 10^{-5}]\\\\pH=5-log1.9\\\\pH=4.72

  • pH Sulfurous acid

\tt pH=-log[10^{-1}]\\\\pH=1

  • pH Nitric acid

\tt pH=-log[11\times 10^{-2}]\\\\pH=2-log~11=0.959

8 0
2 years ago
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