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3 years ago

An example of an atom that has no charge is one that has

2 answers:

7 0

For an atom to have no charge, that is neutral, the number of electrons should be the same to the number of electrons. If the number of electron is more than the number of proton, the atom is negatively charged. Also, when the number of proton is more than the number of electron, the atom is positively charged. The answer to this item is letter C.

finlep [7]3 years ago

3 0

An atom consists of a postively charged nucleus that is surrounded by a negatively charged cloud of electrons . The nucleus consists of positvely charged protons and charge-neutral neutrons. An example of an atom that has no net charge is one that has two protons, two electrons and one neutron (Answer C).

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How many mass would be contained in 0.01mol of NaOH

8_murik_8 [283]

Answer:

∴ No. of atoms in 0.01 moles of NaOH = 6.02×10

×0.01=6.02×10

3 0

2 years ago

The density of red wine is 1.01g/cm3 and the density of olive oil is 0.92g/cm3.A salad dressing that consisted of these two ingr

Sauron [17]

the red wine is the densest so, it will be on bottom olive oil will be on the top. because its less than the red wine

3 0

3 years ago

The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b

tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

$\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}$

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

$\Delta G^0=0$

So,

$Delta H^0_{vap}=T\Delta S^0_{vap}$

Given that:

$Delta H^0_{vap}=55.5\ kJ/mol$

Also, 1 kJ = 10³ J

So,

$Delta H^0_{vap}=55500\ J/mol$

$\Delta S^0_{vap}=148\ J/K.mol$

So, temperature is :

$T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}$

$T=\frac{55500}{148}$

T= 375 K

3 0

3 years ago

How did Democritus contribute to the development of the atom?

matrenka [14]

Democritus developed the atomic model. He theorized that atoms were specific to the material which they composed. He also believed that the atoms different in size and shape, were in constant motion in a void, collided with each other; and during these collisions, could stick together.

6 0

3 years ago

A gas of 19 mL at a pressure of 740 mmHg can be expected to change its pressure when its volume changes to 30. mL. Express its n

Soloha48 [4]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1V1/V2

P2 = 740mmhg x 19 mL / 30 mL

P2 = 468.67 mmHg = 0.62 atm

6 0

3 years ago

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