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Dima020 [189]
3 years ago
5

8..................................

Mathematics
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:

The answer is 2x^{3}y^{-2}\sqrt{6}

Step-by-step explanation:

∵ √24 = 2√6

∵ \sqrt{x^{6}}=(x^{\frac{1}{2}})^{6}=x^{3}

∵ \sqrt{y^{-4}}=(y^{\frac{1}{2}})^{-4}=y^{-2}

∴ \sqrt{24x^{6}y^{-4}}=2x^{3}y^{-2}\sqrt{6}

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azamat
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