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DiKsa [7]
3 years ago
12

4,139 divided by 14 equals what?

Mathematics
2 answers:
Anon25 [30]3 years ago
3 0

Answer:

that would be 57,946

saul85 [17]3 years ago
3 0

Answer: 295.642 (Work is shown below in the image)

Step-by-step explanation:

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What is the equation of a circle with a center located at (-3, 4) and a diameter of 14?
AnnZ [28]

Answer: (x + 3)^2 + (y - 4)^2 = 49

Step-by-step explanation:

The equation of a circle given the center and radius: (x - h)^2 + (y - k)^2 = r^2

Given: center (-3,4) ; h = -3 and k = 4

diameter = 14

To find the radius: divide the diameter by 2 = 14/2 = 7 = r

Center: (-3,4) and radius: 7

Equation of a circle: (x - h)^2 + (y - k) ^2 = r^2

Substitute h = -3, k = 4, r = 7

(x - (-3))^2 + (y - 4)^2 = 7^2

Answer:

Equation of the circle: (x + 3)^2 + (y - 4)^2 = 49

7 0
3 years ago
Simplify: (3²-4)/5 <br>A. 1 <br>B. 1.25 <br>C. 1/5 <br>D. 5​
Nikitich [7]

Answer:

A is the correct answer

Step-by-step explanation:

(9 -4)/ 5

5/5

=1

7 0
3 years ago
Read 2 more answers
A set of scores ranges from a high of x = 96 to a low of x = 11. if these scores were placed in a grouped frequency distribution
bazaltina [42]
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.

The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.

The class width for each data can be calculated as:
 
Class Width = Range / Number of Classes  = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
 
So, the best value of class width or interval width for the given data will be 9.
8 0
3 years ago
Tomas wants to buy a new baseball bat. The one he likes costs $130, but it's one sale for $104. What is the percent of the disco
OLga [1]
130 x .20% = 26
130-26 = 104
So 20%
3 0
2 years ago
Read 2 more answers
Chaim tried to prove that AUTS ~ AUDE in the following figure, but his proof is wrong.
omeli [17]

Answer:

it’s A it is not given the ST and DE are parallel

Step-by-step explanation:

7 0
3 years ago
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