The formula for the volume of a sphere is mc012-1.jpg. What is the formula solved for r?
1 answer:
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The displacement is 18.03 steps, and the direction is 47.25°
<h3>How to get the displacement?</h3>
We know that displacement is the difference between the final position and the initial position.
We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.
First, the student moves 8 steps east, so she is at:
(0 + 8, 0)
Then she moves 6 steps northeast, so the new position is:
(6*cos(45°) + 8, 6*cos(45°))
Finally, she moves 9 steps due north, so we have:
(6*cos(45°) + 8, 6*cos(45°) + 9)
Then the final position is:
(12.24, 13.24)
So the displacement is:
D = (12.24, 13.24) - (0, 0) = (12.24, 13.24)
The magnitude of the displacement is:
So the magnitude is 18.03 steps.
And the direction is given by the arctangent of the quotient between the y-component and the x-component:
If you want to learn more about displacements:
#SPJ1
The resultant graph is shown in the attached image.
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)