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vodomira [7]
3 years ago
14

IS THIS CORRECT!!!????

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0
So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
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What are some easy ways to find the value of<br> (2017^4−2016^4)/(2017^2+2016^2) without calculator
scoray [572]

Answer:

4033

Step-by-step explanation:

An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:

a^2 = 2017^4

a = 2017^2

b^2 = 2016^4

b = 2016^2

Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:

<h3>\frac{(2017^2+2016^2)(2017^2 - 2016^2)}{2017^2+2016^2}</h3>

We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by \frac{2017^2+2016^2}{2017^2+2016^2} which is just one, and will simplify the fraction to just:

2017^2 - 2016^2

This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:

(2017 + 2016)(2017 - 2016)

And, without using a calculator, this is easy to simplify:

(4033)(1)

4033

8 0
2 years ago
The graph shows the distance cars A and B travel.
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3 years ago
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Can anyone give me the answer and tell me how you did it?
pav-90 [236]

Answer:

the answer is 150

Step-by-step explanation:

8 0
3 years ago
Is one side of a rectangular fish tank best represented by a point, line, plane, or ray?
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<span>One side of a rectangular fish tank can be best represented by a plane because it is two dimensional.Whereas,point,line or a ray are all one dimensional and hence they cannot represent a rectangle as it has two dimensions.</span>
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How do you do this question?
mihalych1998 [28]

Answer:

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Step-by-step explanation:

The area under the curve from x=-π/2 to x=k is 3 times the area under the curve from x=k to x=π/2.

\int\limits^k_{-\frac{\pi }{2}} {cos\ x} \, dx = 3\int\limits^{\frac{\pi }{2}}_k {cos\ x} \, dx\\sin\ x\ |^{k}_{-\frac{\pi }{2}} = 3\ sin\ x\ |^{\frac{\pi }{2}}_k\\(sin\ k - (-1)) = 3\ (1 - sin\ k)\\sin\ k + 1 = 3 - 3\ sin\ k\\4\ sin\ k = 2\\sin\ k = \frac{1}{2}\\k = \frac{\pi}{6}

Graph: desmos.com/calculator/mezlen9hb4

3 0
3 years ago
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