Question

Help me solve this intermediate algebra problem

Answer 1

Answer:

x + 1 + 4√(x-3)

Step-by-step explanation:

Given: $(\sqrt{x - 3} + 2)^2$

We know that:  (a + b)² = a² + b² + 2ab

Using this formula, we expand the given expression:

⇒ $(\sqrt{x - 3} + 2)^2 = (\sqrt{x - 3})^2 + 2.\sqrt{x - 3}. 2 + 2^2$

⇒ $x - 3 +4\sqrt{x - 3} + 4$

⇒ $(\sqrt{x - 3} + 2)^2$ = x + 1 +4√(x - 3).