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AlladinOne [14]
2 years ago
14

Anna has 10 to the 2nd power quarters. Jazmin has 10 to the second power dimes Who has more money, Anna or Jasmine? How much mor

e? Explain
Mathematics
1 answer:
Hoochie [10]2 years ago
6 0
Anna has 100 quarters and jazmin has 100 dimes 100 dimes are equal to 10.00 and 100 quarters are equal to 25.00 Anna has more

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A school is selling tickets to their Spring theater production. Student tickets cost $6 each and non-student tickets cost $9 eac
I am Lyosha [343]

Answer:

x=137

y=525-137

y=388

Step-by-step explanation:

Let the student tickets be x

Let the geral Admission tickets be y

x+y=525

y=525-x

4x+6y=2876 (subsitute for y)

4x+6(525-x)=2876

 

4x+3150-6x=2876

-2x=-274

x=137

y=525-137

y=388

Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.

Paul.

3 0
3 years ago
Read 2 more answers
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
tresset_1 [31]

Because I've gone ahead with trying to parameterize S directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over S straight away, let's close off the hemisphere with the disk D of radius 9 centered at the origin and coincident with the plane y=0. Then by the divergence theorem, since the region S\cup D is closed, we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

where R is the interior of S\cup D. \vec F has divergence

\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z

so the flux over the closed region is

\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0

\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}

Parameterize D by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k

with 0\le u\le9 and 0\le v\le2\pi. Take the normal vector to D to be

\vec s_u\times\vec s_v=-u\,\vec\jmath

Then the flux of \vec F across S is

\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0

\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}

8 0
3 years ago
The first term of a sequence is13<br> The term to term is take away 5<br> work out the 4th term
stepladder [879]

Answer:

-2

Step-by-step explanation:

13

8

3

-2

5 0
2 years ago
Read 2 more answers
In how many ways can 6 competitors finish a race assuming there are no ties?In how many ways can we sit n people on r &lt; n cha
VLD [36.1K]

Answer:  a) 720, b) ^nC_r=\dfrac{n!}{(n-r)!r!} c) 336, d) 30240 e) 120.

Step-by-step explanation:

Since we have given that

a) Number of competitors  = 6

We need to find the number of ways that 6 competitors can finish a race and there are no ties.

So, Number of ways would be

6!=720

b) number of people = n

Number of chairs = r (r<n)

so, the number of ways we can sit n people on r<n chairs is given by

^nC_r=\dfrac{n!}{(n-r)!r!}

c) If there are three awards :

Gold, silver, bronze.

We need to find the number of ways that these medals can be awarded.

Number of ways is given by

^8P_3\\\\=336

d) Number of 5-digit zip codes are possible is given by

^{10}P_5=30240

e) Number of poeple = 10

Number of people required in committee = 3

Number of different 3 person committee that are selected from 10 people is given by

^{10}C_3=120

Hence, a) 720, b) ^nC_r=\dfrac{n!}{(n-r)!r!} c) 336, d) 30240 e) 120.

6 0
3 years ago
Help me please with math
koban [17]

Answer:

2) y = x - 4

   y = -x + 2

   => x - 4 = -x + 2

   => 2x = -6

   => x = -3

   => y = -3 - 4 = -7

3) y = 3x + 1

   y = 5x - 3

   => 3x + 1 = 5x - 3

   => 2x = 4

   => x = 2

   => y = 3(2) + 1 = 7

4) 2x + y = 8 => y = -2x + 8

   y = x - 7

   => -2x + 8 = x - 7

   => 3x = 15

   => x = 5

   => y = 5 - 7 = -2

7 0
2 years ago
Read 2 more answers
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