When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?
1 answer:
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Answer:
Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.
Step-by-step explanation:
To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).
We have the following formulas:
, in which i is the number of inches that the woman has above 5 feet.
, in which
is her Actual Body Weight
So, in this problem:
Each pound has 0.45kg. So her weight is kg.
The woman is 8 inches above 5 feet, so .
kg
Her ideal body weight is 63.9kg. Her adjusted body weight is:
kg
Her adjusted body weight is 78.26kg = 78.3kg.