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Keith_Richards [23]
3 years ago
7

35 year old female. 5’8', 220 pounds. Calculate Adjusted Body Weight. (Round to the nearest tenth if applicable): ________

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.

Step-by-step explanation:

To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).

We have the following formulas:

IBW = 45.5kg + 2.3kg*i, in which i is the number of inches that the woman has above 5 feet.

AjBW = IBW + 0.4*(ABW - IBW), in which ABW is her Actual Body Weight

So, in this problem:

Each pound has 0.45kg. So her weight is ABW = 220*0.45 = 99.8kg.

The woman is 8 inches above 5 feet, so i = 8.

IBW = 45.5 + 2.3*8

IBW = 63.9kg

Her ideal body weight is 63.9kg. Her adjusted body weight is:

AjBW = IBW + 0.4*(ABW - IBW)

AjBW = 63.9 + 0.4*(99.8-63.9)

AjBw = 78.26kg

Her adjusted body weight is 78.26kg = 78.3kg.

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