Question

35 year old female. 5’8', 220 pounds. Calculate Adjusted Body Weight. (Round to the nearest tenth if applicable): ________

Answer 1

Answer:

Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.

Step-by-step explanation:

To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).

We have the following formulas:

$IBW = 45.5kg + 2.3kg*i$, in which i is the number of inches that the woman has above 5 feet.

$AjBW = IBW + 0.4*(ABW - IBW)$, in which $ABW$ is her Actual Body Weight

So, in this problem:

Each pound has 0.45kg. So her weight is $ABW = 220*0.45 = 99.8$kg.

The woman is 8 inches above 5 feet, so $i = 8$.

$IBW = 45.5 + 2.3*8$

$IBW = 63.9$kg

Her ideal body weight is 63.9kg. Her adjusted body weight is:

$AjBW = IBW + 0.4*(ABW - IBW)$

$AjBW = 63.9 + 0.4*(99.8-63.9)$

$AjBw = 78.26$kg

Her adjusted body weight is 78.26kg = 78.3kg.