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Montano1993 [528]
2 years ago
8

Which expression shows (45 + 15) in the form a(b+c) where a is the greatest common factor

Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0

Answer:

answer is a. 15(3+1)

Step-by-step explanation:

um this makes sense lmk if I'm wrong

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Evaluate 4z divided 7 for z=35
Alex787 [66]
Plug 35 in for z. Multiply 4 and 35 to get 140 then divide by 7 to get 20
4 0
3 years ago
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Find the range of the given data set.<br><br> -4, -3, -1, -1, 0, 1
Dovator [93]

Answer:

5

Step-by-step explanation:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

7 0
4 years ago
For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9
Nezavi [6.7K]

Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

6 0
4 years ago
What is 3760 over 7916 reduced?
umka2103 [35]

3760/7916

reducing this fraction is simplifying it, so that means

3760/7916=940/1979

7 0
4 years ago
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CSEL gets very crowded when homework is due, or when there is a test for Intro to Data Science. Let T denote the random variable
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Answer:

5 minutes

Step-by-step explanation:

If the mean arrival rate is 0.2 students per minute, the expected time interval between student arrivals, in minutes, is determined by the inverse of the arrival rate:

t = \frac{1}{\lambda}=\frac{1}{0.2}=5\ minutes

The interval between student arrivals is, on average, 5 minutes.

7 0
4 years ago
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