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2 years ago

Which expression shows (45 + 15) in the form a(b+c) where a is the greatest common factor

Mathematics

1 answer:

4vir4ik [10]2 years ago

4 0

Answer:

answer is a. 15(3+1)

Step-by-step explanation:

um this makes sense lmk if I'm wrong

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In order for Josh to graph the solution to the inequality 4x - 2y > 6, which of the following steps does he need to use? Sele

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B:Solve the inequality as y < 2x-3.

D:Draw the line y=2x-3 as a dashed line.

E:Shade below the line.

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3 years ago

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What is the simple interest earned on $300 over 6 years at 4% interest?

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Answer:

$72

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3 years ago

Dan wants to collect data about the eating habits of his friends.

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A) What time of the day do my friends eat their biggest meal?

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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3 years ago

What is the equation of the line that goes through (−1, −1) and is parallel to y = 6x − 1?

Alexandra [31]

Y-y1 = m(x-x1)
y-(-1) = 6 (x- -1)

answer: y = 6x-5

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3 years ago