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2 years ago

What are the quotient and remainder of (3x^4+ 2x^2 - 6x + 1) /(x + 1)

Mathematics

1 answer:

quester [9]2 years ago

4 0

Answer:

all work is shown and pictured

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Triangle abc is similar to triangle FGH solve for p plebs.

12345 [234]

The value of p is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

$\frac{ab}{fg} = \frac{bc}{gh} \\ \frac{35}{p} = \frac{10}{6} \\ p = \frac{35 \times 6}{10} \\ p = \frac{210}{10} \\ p = 21 \\ \\ or \\ \\ \frac{ab}{fg} = \frac{ac}{fh} \\ \frac{35}{p} = \frac{30}{18} \\ p = \frac{35 \times 18}{30} \\ p = \frac{630}{30} \\ p = 21$

So, the value of p is 21

Hope it helpful and useful :)

5 0

3 years ago

PLS HELP!!! Thank You!!!

denis-greek [22]

Answer:

21 years

Step-by-step explanation:

Given

Required

Determine the years it'll take to grow to the final height

This question depicts arithmetic progression and will be solved using

Where

Substitute these values in the given formula;

Convert all fractions to decimal

Open Brackets

Collect Like Terms

Divide both sides by 1.75

Then you have your answer.

Hope this helped!!<3

8 0

2 years ago

Read 2 more answers

He initially had 300 boxes of candy. Every minute he sells 4 boxes. WHAT IS THE SLOPE?

enot [183]

The slope is -4/1. Hope this helps

5 0

3 years ago

Ishaan and his friends have 40$ to spend at a restaurant.

Paul [167]

The number of salads Ishaan and his friends can afford is 6 salads.

<h3>What are Word Problems?</h3>

Word Problems in mathematics involve crucial understanding and the use of variables and arithmetic operations to solve real-life cases.

From the given information;

The total amount with Ishaan and his friends = $40
If they decided to spend the money on salad(x) and one salad(x) cost = $6

Thus, the number of salads they can purchase is:

$\mathbf{x = \dfrac{\$40}{\$6}}$

x = 6 salads remaining $4

Therefore, we can conclude that the number of salads they can purchase with $40 is 6 salads with a remaining amount of $4.

Learn more about word problems here:

brainly.com/question/21405634

3 0

2 years ago

In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67

Mashcka [7]

Answer:

Standard Error of the difference = 0.0695

Step-by-step explanation:

Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

$\implies P_1=\frac{16}{85}\\\\n_1=85$

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

$\implies P_1=\frac{19}{67}\\\\n_2=67$

Now, finding the standard error of the difference :

$\text{Standard Error = }\sqrt{\frac{P_1(1-P_1)}{n_1}+\frac{P_2(1-P_2)}{n_2}}\\\\\implies \text{Standard Error = }\sqrt{\frac{\frac{16}{85}(1-\frac{16}{85})}{85}+\frac{\frac{19}{67}(1-\frac{19}{67})}{67}}\\\\\implies\text{Standard Error = }0.0695$

Hence, Standard Error of the difference = 0.0695

6 0

3 years ago

Read 2 more answers