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const2013 [10]
3 years ago
10

B.s. is parallel to xy what is the value of x

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

A. 85

Step-by-step explanation:

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A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
fenix001 [56]

Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0
3 years ago
Using GCF and the distributive property, write two equivalent expressions for 30+45?
yaroslaw [1]
5x15, 3x25 because 30+45=75 and both 5x15 and 3x25 equal 75
6 0
3 years ago
1. Which expression is equivalent to the expression below?
Nat2105 [25]

Answer:

B. 48x - 56

Step-by-step explanation:

8(6x - 7) \\  = 8 \times 6x - 8 \times 7 \\  = 48x - 56

8 0
3 years ago
Please help me thanks!​
lions [1.4K]
5 x 16 x 4 = 320 m^3
3 0
3 years ago
Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5
abruzzese [7]

Answer:

The answer is <em>1</em>.

Step-by-step explanation:

Given the expression:

|z-6|-|z-5|,\ if\ z

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

y = f(x) = |x| =\left \{ {{x\ if\ x>0} \atop {-x\ if\ x

i.e. value is x if x is positive

value is -x if x is negative

Here the given expression contains two absolute value functions:

|z-6| and |z-5|

Using the definition of absolute value function as per above definition.

|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z

|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression |z-6|-|z-5|,\ if\ z will be equivalent to :

-(z-6) - (-(z-5))\\\Rightarrow -z+6 +z-5 = \bold{1}

So, the expression is equivalent to <em>1</em>.

6 0
3 years ago
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