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Flura [38]
3 years ago
14

I GIVE BRAINLIEST :) Question is in picture, tysm

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

No x^3 times x^5 is not equal to x^15. It is equal to x^8

Step-by-step explanation:

x3x5

=x3*x5

=(x*x*x)*(x*x*x*x*x)

=x*x*x*x*x*x*x*x

=x8

olga nikolaevna [1]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

x^{3}  = x*x*x\\x^{5}  = x*x*x*x*x\\x^{3} x^{5} = x*x*x*x*x*x*x*x = x^{8} ≠ x^{15}

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The time t that it takes for a group of volunteers to construct a house varies inversely as the number of volunteers v. If 20 vo
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20 \div 15 = 1 \dfrac{1}{3}
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Answer is 83.3 hours.

Hope this helps. - M
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3 years ago
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What are the three consecutive even integers that add up to 156
son4ous [18]
First, divide 156 by 3 (the amount of consecutive integers).
156 / 3 = 52
The middle consecutive integer is 52. Add and subtract 52 by 2.
52 - 2 = 50
52 + 2 = 54
Your three integers are 50, 52, and 54. Have an awesome day! :)
5 0
3 years ago
What is long divison
pochemuha

Answer:arithmetical division in which the divisor has two or more figures, and a series of steps is made as successive groups of digits of the dividend are divided by the divisor, to avoid excessive mental calculation.

Step-by-step explanation:

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7 0
3 years ago
Mr. Ratchett, an elderly American, was found murdered in his train compartment on the Orient Express at 7 AM. When his body was
lubasha [3.4K]

Answer:

Time of Death = 2 : 49 : 45 AM

Step-by-step explanation:

The formula for Newton's Law of Cooling is written as follows:

dT/dt = - K(T - Ts)

where,

dT = change in temperature

dt = time interval

K = cooling constant

T = Final Temperature of object

Ts = Surrounding Temperature

First, we will use the data of cooling of body from 28°C to 27°C to find the cooling constant of the body:

dT = 27°C - 28°C = -1°C

dt = 1 hr = 3600 s

K = ?

T = 27°C

Ts = 22°C

Therefore,

-1 °C/3600 s = - K(27 °C - 22 °C)

K = 1 °C/(3600 s)(5 °C)

K = 5.55 x 10⁻⁵ /s

Now, we use data for cooling of body from 37 °C to 28 °C to find the time of death:

dT = 28°C - 37°C = -5°C

dt = ?

K = 5.55 x 10⁻⁵ /s

T = 28°C

Ts = 22°C

Therefore,

- 5 °C/dt = - (5.55 x 10⁻⁵ /s)(28 °C - 22 °C)

dt = 5 °C/(5.55 x 10⁻⁵ /s)(6 °C)

dt = 1.5 x 10⁴ s

dt = 4.17 h = 4 h 10 min 15 s

Therefor,

Time of Death = 7 : 00 : 00 AM - 4 : 10 : 15

<u>Time of Death = 2 : 49 : 45 AM</u>

3 0
3 years ago
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