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3 years ago

What is the result of subtracting the second equation from the first?

Mathematics

2 answers:

Dovator [93]3 years ago

4 0

Answer:

-5x+7

Step-by-step explanation:

butalik [34]3 years ago

3 0

Answer:

-5x + 7

Step-by-step explanation:

-4x - 2y = -2

x - 2y = 9

First, you're going to subtract the equations from each other.

(-4x - 2y = -2) - (x - 2y = 9)

Next, you need to get rid of the equal sign in both equations.

(-4x - 2y = -2) - (x - 2y = 9)

+2 +2 -9 -9

After you get rid of the equal signs, you will distribute the sign to the equation and then subtract everything.

-4x - 2y + 2 - x + 2y + 9

Now, combine the like terms.

(-4x -x) + (-2y + 2y) + (2 + 9)

Finally, calculate the terms and solve.

-5x + 7

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2 years ago

Landon scored an 85% on his test. If he got 34 problems correct, how many were on the test?

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Answer:

There are 40 problems on the test

Step-by-step explanation:

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6 0

2 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago

What is the result of subtracting the second equation from the first?​

What is the result of subtracting the second equation from the first?