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Olin [163]
3 years ago
12

Find measure jk Answers are 52, 128, 154 & 180

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

b. 128°

Step-by-step explanation:

arc LJ = 2 (26) = 52°

arc KL = 180° (half circle)

so

arc JK = 360° - (arc LJ + arc KL)

arc JK = 360° - 232°

arc JK = 128°

Answer

b. 128°

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The ratio of dogs to cats at a local animal shelter is 13/25. Which statement must be true?
Ivan

<em>Option:</em>

<em>a. for every 13 dogs, there are 25 cats. </em>

<em>b. there are twice as many cats as dogs at the shelter. </em>

<em>c. the shelter has more dogs than cats. </em>

<em>d. there are 25 animals in the shelter.</em>

Answer:

a. for every 13 dogs, there are 25 cats.

<em></em>

Step-by-step explanation:

Represent Dogs with D and Cats with C;

So;

\frac{D}{C} = \frac{13}{25}

By comparison:

D=13

C = 25

This implies that:

For every 13 D, there are 25 C

Hence: Option A is true

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Q1 Express in the form 1.0<br> 4:12
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Step-by-step explanation:

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3 0
3 years ago
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
2 years ago
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