Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
Answer:
i believe it's 12 but i'm not entirely sure
Step-by-step explanation:
i hope this helps :) please let me know if it was wrong
have a nice day !!
<span>Total Cost/Price: 529.74
</span>Total Tax: <span>39.24
</span>
7x+8(x+1/4) = 3(6x-9)-8
7x+8x+2 = 18x - 27 -24
15x + 2 = 18x - 51
+51 + 51
15x + 53 = 18x
-15x = -15x
53 = 3x
17.66 = x
Answer:
15
-----
32
Step-by-step explanation:
3 5 15
-- * -- == ---
4 8 32
