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4 years ago

What is the answer to 6(-3m)^4

Mathematics

1 answer:

Sergio [31]4 years ago

6 0

Answer:
486m^4
If this ^ means exponents.

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23n=2.4 A. 3.6 B. 7.2 C. 1.2 D. 1.6

svp [43]

$\huge\text{Hey there!}$

$\mathsf{23n =2.4}$

$\large\text{DIVIDE 23 to BOTH SIDES}$

$\mathsf{\dfrac{23n}{23}=\dfrac{2.4}{23}}$

$\large\text{Cancel out: }\mathsf{\dfrac{23}{23}}\large\text{ because it gives you 1}$

$\large\text{Keep: }\mathsf{\dfrac{2.4}{23}}\large\text{ because it helps us solve for n}$

$\mathsf{n = \dfrac{2.4}{23}}$

$\mathsd{\dfrac{2.4}{23}= 2.4\div 23\rightarrow \bf 0.104348}$

$\boxed{\boxed{\large\textsf{Answer: \huge n = \bf 0.104348}}}\huge\checkmark$

$\boxed{\textsf{NONE OF THE ABOVE is your ANSWER}}$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

3 years ago

Solve the system of linear equations by ellmination. 5x + 9y = -11 3x + 9y = -3 A. (-4,-1) -B. (-1, –4) C. (-4,1) D. (1,-4)

valentina_108 [34]

Answer:

Step-by-step explanation:

5x + 9y = -11

3x + 9y = -3

5x + 9y = -11

-3x - 9y = 3

2x = -8

x = -4

-12 + 9y = -3

9y = 9

y = 1

(-4, 1)

Answer is C

5 0

3 years ago

5. SLOPE need help like, ASAP, tysm

Papessa [141]

Answer:

Since it's a horizontal line the slope would be 0

Step-by-step explanation:

Horizontal Lines A horizontal line is a line whose equation is of the form =, where is a real number. All points that lie on the line have a -coordinate of . The slope of any horizontal line is zero, 0.

3 0

3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

3 years ago

What is the image point of (-7,0) after a translation left 4 units and up 1 unit?

ivann1987 [24]

Answer:

(-11, 1)

Step-by-step explanation:

x-values are horizontal and y-values are vertical

so add -4 to -7 to get -11

add 0 to 1 to get 1

new point is at (-11,1)

7 0

3 years ago