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SashulF [63]
3 years ago
6

Given right triangle ABC, what is the value of tan(A)?

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0
The value of tan(A) is C. 12/5
Angelina_Jolie [31]3 years ago
7 0
You didn't provide more information regarding triangle but from given options, it seems that triangle has ratio from shortest side to longest side would be 5 : 12 : 13

So 13 would be hypotenuse since it is longest.

Now A cannot be right angle because tangent is not defined at 90°.

Also tan(A) would be ratio of opponent side to adjacent side (think SOH CAH TOA)

So either opposite side would be 5 or 12, and adjacent side would be 12 or 5 respectively.

So the answer is either 5 / 12 or 12 / 5 but only option provided is 12/5 so that would be your answer.

Final answer: 12 / 5
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Solve the equation: x-10 - 2x + 7 = 8 + x - 10 - 3x
Minchanka [31]

Answer: If you're looking for the value of x, it's 1.

Step-by-step explanation:

Add the numbers. x-10-2x+7=8+x-10-3x--->x-3-2x=8+x-10-3x

Combine like terms. x-3-2x=8+x-10-3x ---> -x-3=8+x-10-3x

Subtract the numbers.-x-3=8+x-10-3x---> -x-3=-2+x-3x

Combine like terms. -x-3=-2+-3x---> -x-3=-2-2x

Rearrange terms. -x-3=-2-2x---> -x-3=-2x-2

Hope that helps!

4 0
3 years ago
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vitfil [10]

Answer:

It's called diagonal

8 0
2 years ago
approximately 13% of the USA population is left handed. Hiw many lefties would expect in a school of 420 students​
Alex Ar [27]

Answer:

Approximately 55 students

Step-by-step explanation:

13% of 420 is 54.6 which you can then round up to 55

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3 years ago
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Suppose P(t)represents the population of a certain mosquito colony, where. t is measured in days. The current population of the
Darina [25.2K]

Answer:

The estimated size of the population in 10 days is of 1372 mosquitos.

Step-by-step explanation:

Population after t days:

The population after t days is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial population and r is the growth rate, as a decimal.

P(0)=574.

So

P(t) = 574e^{rt}

P'(0)=50

P^{\prime}(t) = 574re^{rt}

Since P'(0)=50

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So

P(t) = 574e^{0.0871t}

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This is P(10).

P(10) = 574e^{0.0871*10} = 1372

The estimated size of the population in 10 days is of 1372 mosquitos.

4 0
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