Question

What are the solutions of the quadratic equation below?

Answer 1

Use the quadratic formula -b +/-√(b^2-4(ac)) / 2a

In the given formula a = 7, b = 23 and c = -10

Replace the letters with their values:

-23 +/-√(23^2 -4*(7*-10)) / 2*7

Simplify to get:

x = -23 + √809 / 14 or x = -23 - √809 / 14

Answer 2

Answer:

$x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}$

Step-by-step explanation:

Given : $-7x^2 - 23x + 10 = 0$

To Find: What are the solutions of the quadratic equation below?  

Solution:

$-7x^2 - 23x + 10 = 0$

Solve the given equation using quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

General form of quadratic equation: $ax^2+bx+c=0$

On Comparing given equation with general form

a = -7

b = -23

c = 10

Substitute the values in the formula:

$x=\frac{-(-23)\pm\sqrt{(-23)^2-4(-7)(10)}}{2(-7)}$

$x=\frac{23\pm\sqrt{809}}{-14}$

$x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}$

Hence the solution of the quadratic equation is $x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}$