Answer:
Passive range of motion can be defined as what is achieved when an outside force, such as a therapist, causes movement of a joint. It is usually the maximum range of motion. Active range of motion is what can be achieved when opposing muscles contract and relax, resulting in joint movement
Answer:
Explanation:
Path difference for the destructive interference of a single slit:
For the first - order minimum, n = 1, and
.........(1)
For the second - order minimum, n = 2, and
.........(2)
Dividing equation (2) by equation (1):
Answer:
5.66 × 10⁻²³ m/s
Explanation:
If i assume i can jump as high as h = 2 m, my initial velocity is gotten from v² = u² + 2gh. Since my final velocity v = 0, u = √2gh = √(2 × 9.8 × 2) = √39.2 m/s = 6.26 m/s.
Since initial momentum = final momentum,
mv₁ + MV₁ = mv₂ + MV₂ where m, M, v₁, V₁, v₂ and V₂ are my mass, mass of earth, my initial velocity, earth's initial velocity, my final velocity and earth's final velocity respectively.
My mass m = 54 kg, M = 5.972 × 10²⁴ kg, v₁ = 6.26 m/s, V₁ = 0, v₂ = 0 and V₂ = ?
So mv₁ + M × 0 = m × 0 + MV₂
mv₁ = MV₂
V₂ = mv₁/M = 54kg × 6.26 m/s/5.972 × 10²⁴ kg = 338.093/5.972 × 10²⁴ = 56.61 × 10⁻²⁴ m/s = 5.661 × 10⁻²³ m/s ≅ 5.66 × 10⁻²³ m/s
<h2>
25.32 N net force would give the same object an acceleration of 3.9 m/s²</h2>
Explanation:
We have
Force = Mass x Acceleration
A net force of 37 N gives an object an acceleration of 5.7 m/s²
F = ma
37 = m x 5.7
m = 6.49 kg
Now we need to find what net force would give the same object an acceleration of 3.9 m/s²
Force = Mass x Acceleration
Force = 6.49 x 3.9
Force = 25.32 N
25.32 N net force would give the same object an acceleration of 3.9 m/s²
Answer:
it helps you estimate how hard you're working (your activity intensity). <u>perceived exertion</u> is how hard you think your body is exercising. ratings on the scale are related to heart rate (how hard your heart is working to move blood through your body).
Explanation: