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Andru [333]
3 years ago
8

A SpaceX rocket launched from the Boca Chica space port must attain a speed of 10000 m/s during the first 6 minutes of flight. U

sing the first equation of motion, determine the acceleration needed for a succesful take off.
Physics
1 answer:
salantis [7]3 years ago
5 0

Answer:

27.78 m/s²

Explanation:

t = Time taken = 6 minutes

u = Initial velocity = 0 (assuming it started from rest)

v = Final velocity = 10000 m/s

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

First equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{10000-0}{6\times 60}\\\Rightarrow a=27.78\ m/s^2

Acceleration of the rocket is 27.78 m/s²

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Kinetic energy is the energy of . It increases with and .Potential energy is the energy of or . It increases with , and
lorasvet [3.4K]

Answer:

k is the energy of motion it increase with four of load you carry

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3 years ago
What is the formula to find initial velocity?​
Inga [223]

Answer:

s = ut + 1/2at^2

Explanation:

s= distance

u= initial velocity

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7 0
3 years ago
Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.
Mars2501 [29]

Answer:

0.5\times 10^{-6}C

Explanation:

According to coulombs law force between two charges is given by F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2} here R is the distance between both the charges which is given as 25 cm

We have given force F =0.036 N

So  0.036=\frac{1}{4\pi \times 8.85\times 10^{-12}}\frac{Q^2}{(0.25^2)} As \epsilon _0 is constant which value is 8.85\times 10^{-12}

Q^2=0.250\times 10^{-12}

Q=0.5\times 10^{-6}C

8 0
3 years ago
What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o
leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,  

d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}

This value can be used to determine the time for the pellet through the barrel:

t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s

Finally, we can use the above to calculate the force:

F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N



8 0
3 years ago
Electric field lines always begin at _______ charges (or at infinity) and end at _______ charges (or at infinity). One could als
victus00 [196]

Electric field lines always begin at positive charges (or at infinity) and end at negative charges (or at infinity).

One could also say that the lines we use to represent an electric field indicate the direction in which a positive test charge would initially move when released from rest.

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4 years ago
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