All categories

3 years ago

Find X when y= -2 Thank you for your help and have a blessed day

Mathematics

2 answers:

Andreas93 [3]3 years ago

8 0

Answer:

x = -5

Step-by-step explanation:

$4x+y=2(x+3y)\\\\4x-2=2(x+3(-2))\\\\4x-2=2(x-6)\\\\4x-2=2x-12\\\\4x-2+2=2x-12+2\\\\4x=2x-10\\\\4x-2x=2x-2x-10\\\\2x=-10\\\\\frac{2x=-10}{2}\\\\\boxed{x=-5}$

Hope this helps.

bekas [8.4K]3 years ago

7 0

Answer:

-5

Step-by-step explanation:

4x+y=2(x+3y)

plug in -2 for y: 4x+(-2)=2(x+3(-2))

solve: 4x-2=2x-12

subtract 2x from each side: 4x(-2x)-2=2x(-2x)-12

2x-2=-12

add 2 to each side: 2x-2(+2)=-12(+2)

2x=-10

divide both sides by 2: 2x(/2)=10(/2)

x=-5

You might be interested in

Jose can read 7 pages of his book in5 minutes. at this rate, how long will it take him to read the entire 175-page book?

Lera25 [3.4K]

Since 7 pages could be in 5 min.
So time required by 1 page 5/7 min.
So time required by 175 pages =175×5/7=125 min.
= 2 hours and 5minutes

8 0

3 years ago

PLEASE HURRY IM TIMED, The perimeter of a rectangular swimming pool is 70 yards. Its length is 25 yards. Which of the following

kolezko [41]

I thik the option C should be used.

5 0

2 years ago

Read 2 more answers

The tip for a restaurant bill is $9.20. What is the tip for a 21.50 meal?

nlexa [21]

The amount of the tip is 12%

8 0

4 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago

3x+4y= 12 and 2x-y=8

Anettt [7]

i dont no sorry :(

..................

4 0

3 years ago