Opposite angles in a cyclic quadrilateral add up to 180 degrees .
So the angle opposite angle A ( that is angle C) must be 180-95 = 85 degrees
1 = 1 x 10 exponent 0
27.5 = 2.75 x 10 exponent 1
Answer:
a=16
Step-by-step explanation:
16/4+2 = 6
Thus the answer is 16
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
Answer:
See solution below
Step-by-step explanation:
Let the coordinate's of A and B be (1, 0) and (2,4) respectively
midpoint M (X, Y) = [(x1+x2/2, y1+y2/2)]
X = x1+x2/2
X = 1+2/2
X = 3/2
X = 1.5
Y = y1+y2/2
Y = 0+4/2
Y = 4/2
Y = 2
Hence the required midpoint (X, Y) is (1.5, 2)
Slope m = y2-y1/x2-x1
m = 4-0/2-1
m = 4/1
m = 4
Hence the slope is 4
<em>Note that the coordinates are assumed but the same calculation can be employed for any other coordinates</em>
