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4 years ago

Elvaluate 3^-2 jgigjdkcjcivkxjgfnv

Mathematics

1 answer:

BARSIC [14]4 years ago

4 0

Answer:

1/9

Step-by-step explanation:

when you have a negative exponent, you move the term to the denominator: 1/3^2

then you just do 3^2: 1/9

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Find the value of x for which a || b. Then find the measure of the labeled angles.

Alchen [17]

Answer:

The measure of the labeled angles is 135°

Step-by-step explanation:

we know that

if a || b

then

$(3x-27)\°=(2x+27)\°$ -----> by alternate exterior angles

Solve for x

$3x-2x=27+27$

$x=54$

Find the measure of the labeled angles

$(3(54)-27)\°=135\°$

6 0

3 years ago

Determine if 7, 8, and 13 can be the lengths of the sides of a triangle. If yes, classify the triangle.

Alona [7]

To determine if 7, 8 and 13 can make a triangle, let's use Pythagorean theorem!

Pythagorean theorem: a² + b² = c²

Now plugging in our numbers: 7² + 8² ≠ 13²

Sadly, these numbers don't work. Therefore we cannot classify the triangle.

Hope this helps!

5 0

4 years ago

Simplify the expression below. (x^25)^-5/(x^-3)^48

marin [14]

Okay so I need to have at least 20 characters to share my answer but I got x^19

4 0

3 years ago

Find the range of f(x) = 5x - 4 for the domain = {2, 4, 6}]

Sphinxa [80]

Answer:

Step-by-step explanation:

For this question they are asking you to find y when x is {2, 4, and 6}

That means you need to plug 2,4, and 6 into the equation and solve.

For example:

f(x) = 5x - 4

f(2) = 5(2) - 4

f(2) = 10 - 4

f(2) = 6

f(x) = 5x - 4

f(4) = 5(4) -4

f(4) = 20 - 4

f(4) = 16

f(x) = 5x - 4

f(6) = 5(6) - 4

f(6) = 30 - 4

f(6) = 26

8 0

3 years ago

I need a lot of help from the smartest people now right now

Dominik [7]

Answer:

K) I, II, and III

Step-by-step explanation:

Given the quadratic equation in standard form, h = -at² + bt + c, where h is the height or the projectile of a baseball that changes over time, t. In the given quadratic equation, c represents the constant term. Altering the constant term, c, affects the h-intercept, the maximum value of h, and the t-intercept of the quadratic equation.

<h2>I. The h-intercept</h2>

The h-intercept is the value of the height, h, when t = 0. This means that setting t = 0 will leave you with the value of the constant term. In other words:

Set t = 0:

h = -at² + bt + c

h = -a(0)² + b(0) + c

h = -a(0) + 0 + c

h = 0 + c

h = c

Therefore, the value of the h-intercept is the value of c.

Hence, altering the value of c will also change the value of the h-intercept.

<h2>II. The maximum value of h</h2>

The maximum value of h occurs at the vertex, (t, h ). Changing the value of c affects the equation, especially the maximum value of h. To find the value of the t-coordinate of the vertex, use the following formula:

t = -b/2a

The value of the t-coordinate will then be substituted into the equation to find its corresponding h-coordinate. Thus, changing the value of c affects the corresponding h-coordinate of the vertex because you'll have to add the constant term into the rest of the terms within the equation. Therefore, altering the value of c affects the maximum value of h.

<h2>III. The t-intercept</h2>

The t-intercept is the point on the graph where it crosses the t-axis, and is also the value of t when h = 0. The t-intercept is the zero or the solution to the given equation. To find the t-intercept, set h = 0, and solve for the value of t. Solving for the value of t includes the addition of the constant term, c, with the rest of the terms in the equation. Therefore, altering the value of c also affects the t-intercept.

Therefore, the correct answer is Option K: I, II, and III.

5 0

3 years ago