The answer is A hehe
There are 10 roller coasters at 6 flags, and you only have time to ride 3 before the park closes. How many different ways can yo
2 answers:
You might be interested in
Complete Question:
Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.
(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.
(b) Determine the scale factor from the first map to the second map.
(c) A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?
(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:
Answer:
(a) Length = 4cm
(b) Scale factor = 0.5
(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale
(d) See attachment for triangle
Step-by-step explanation:
(a) Choose a length between 5 cm and 15 cm
<em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>
(b) The scale factor
The scale factor (k) is calculated as:
(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark
Using:
The old lengths, in this case are: 3cm, 4cm and 5cm
Make New length the subject
When
When
When
So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale
(d) See attachment for triangle
Answer:
The sample has not met the required specification.
Step-by-step explanation:
As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow
: The true average penetration is 50 mils
: The true average penetration is > 50 mils
Since we are trying to see if the true average is greater than 50, this is a right-tailed test.
If the <em>level of confidence</em> is α = 0.05 then the score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)
The z-score associated with this test is
where
= <em>mean of the sample</em>
= <em>average established by the specification</em>
s = <em>standard deviation of the sample</em>
n = <em>size of the sample</em>
Computing this value of z we get z = 3.42
Since z > we can conclude that the sample has not met the required specification.