Answer:
A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.
(a) Find the probability that she is successful for the first time on the third throw:
The number F of unsuccessful throws till the first bull’s eye follows a geometric
distribution with probability of success q = 0.2 and probability of failure p = 0.8.
If the first bull’s eye is on the third throw, there must be two failures:
P(F = 2) = p
2
q = (0.8)2
(0.2) = 0.128.
(b) Find the probability that she will have at least three failures before her first
success.
We want the probability of F ≥ 3. This can be found in two ways:
P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .
= p
3
q + p
4
q + p
5
q + p
6
q + . . . (geometric series with ratio p)
=
p
3
q
1 − p
=
(0.8)3
(0.2)
1 − 0.8
= (0.8)3 = 0.512.
Alternatively,
P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))
= 1 − (q + pq + p
2
q)
= 1 − (0.2)(1 + 0.8 + (0.8)2
)
= 1 − 0.488 = 0.512.
(c) How many throws on average will fail before she hits bull’s eye?
Since p = 0.8 and q = 0.2, the expected number of failures before the first success
is
E[F] = p
q
=
0.8
0.2
= 4.
S+g=316 "s"=strawberry "g"=grape
g=52+s
plug in for "g" to find "s"
s+(52+s)=316
2s+52=316
2s=316-52
2s=264
s=264/2
s=132
find "g"
g=52+132
g=184
Answer:
1) m<1 = 25
2) m<4 = 155
3) m< 5 = 25
4) m<7 = 25
5) 110
6) 30.5
7) 74
Step-by-step explanation:
1)
x + 155 = 180
x = 25
2)
<4 = 155 because of vertical angle thm
3)
<5 = 25 (congruent to <1) b/c of corresponding angles thm
4)
<7 = <5 (25) because of vertical angles thm
5)
5x + 15 = 8x - 42
-3x = -57
x = 19
5(x) + 15
5(19) + 15 = 110
6)
180 - 110 = 70
3x + x + 4 + 70 = 180
4x + 74 = 180
4x = 106
x = 26.5
x+ 4 = 30.5
7)
180 - 115 = 65
x + 4 + 2x + 65 = 180
3x + 69 = 180
3x = 111
x = 37
2x = 74
Answer : d
explanation : i did that question before
Answer:
None of the above.
Step-by-step explanation:Yes, all of the sides match, which would make it an equilateral polygon. However, it is not an equiangular polygon because not all of the angels are the same. In this case, since the angles do not mach and only the sides do, this is not a regular polygon. This is what leads me to believe that is none of them. All of the sides must be congruent and all interior angles must also be congruent.
