Question

ZABD and ZCBD are adjacent. Given that m_ABC is 68º. MZABD= (2x + 5)º, and mZCBD= (3x+8)º, find mZCBD.

Answer 1

Answer:

I think that the required options are wrong.

Answer is given below with explanations.

mZCBD = 41 degrees

Step-by-step explanation:

$from \: the \: \: above \: mentioned \: diagram \\ we \: can \: say \: that \: \\( angle \: ABD) + (angle \: DBC) = 68 \\ given \: that \: \: angle \: ABD = 2x + 5 \\ and \: \: angle \: CBD = 3x + 8 \\ on \: substituting \: the \: values \\ (2x + 5) + (3x + 8) = 68 \\ 5x + 13 = 68 \\ 5x = 68 - 13 \\ 5x = 55 \\ x = \frac{55}{5} \\ x = 11 \\ angle \: CBD = 3x + 8 \\ \: \: = 3(11) + 8 \\ \: \: = 33 + 8 \\ \: \: angle \: CBD= 41$

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