First, Joe started the water and it was at full force. He filled it up to 9 inches. It took him 2 minutes to get to 9 inches. Then, he stopped it for 2 minutes because his mom called him to get a bar of soap. The water level was still at 9 inches when he stopped it. Then, he put the water to come down slowly because he wasn’t sure how much more he needed. He let the water go for 2 minutes. Then, he stopped the water when it was at 12 inches of water. He sat in the bath for 5 minutes until he decided he was to cold so he hopped out. The water then drained really fast. From 12 inches to 0 inches it took the bath 3 minutes.
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

The answer would be 30.
60/2 = 30
90/2 = 45
120/2 = 60