X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer
14 degrees
Step-by-step explanation:
Answer:
30.2
Step-by-step explanation:
Answer:
a1 = 0.5; common ratio = 5
Step-by-step explanation:
Let the common ratio = r
a2 = 2.5
a3 = 2.5r
a4 = 2.5r * r = 2.5r^2
We are told a4 = 62.5, so
2.5r^2 = 62.5
Divide both sides by 2.5
r^2 = 25
r = 5
a2 = a1 * r
a1 = a2/r = 2.5/5 = 0.5
Answer: a1 = 0.5; common ratio = 5
