Answer:
i need help on that one to lol
Step-by-step explanation:
Step-by-step explanation:
here,,
a=3,b=10,C=120°
c^2=a^2+b^2-2ab cos120°
=(3)^2 +(10)^2 _2 (3)(10)(-1/2) [cos120°=-1/2]
=9+100-(-30)
=109+30
=139
c=(139 )1/2=11.79
c=12
Answer:
D
Step-by-step explanation:
Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer: 19 macaroons
Step-by-step explanation:
Let's create an equation to represent this situation. Let x represent the number of macaroons that Em made.
33=x+x+5
33=2x+5
33-5=2x+5-5
28=2x
28/2=2x/2
14=x
This means that Em made 14 macaroons.
14+5=19
Therefore, Jim baked 19 macaroons.