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3 years ago

Can you help me with this question? Thanks!

Mathematics

1 answer:

Natali5045456 [20]3 years ago

5 0

Answer: 11 people like vanilla.

Step-by-step explanation: There are 50 people in this question. Since 22% of them like vanilla, multiply 0.22 and 50. That gives you 11. Therefore, 11 people out of 50 like vanilla.

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This month, 1,500 new members joined a particular health club.the club's goal for thos month was 2,000 new members.What percenta

Sergeeva-Olga [200]

I believe the answer would be 75% of the clubs goal was achieved. I hope this helps!!

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4 years ago

Mark has a checking account. His opening balance on 1/7 was $110. The bank charges a 25¢ fee for each debit card transaction and

ipn [44]

110+30-(15+0.25)+40-(8+0.25)=156.5

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3 years ago

Calculate the average rate of change for the graphed sequence from n = 1 to n = 3.

belka [17]

Answer:

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Step-by-step explanation:

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3 years ago

100 points and brainest Plz help me PLZ

svp [43]

Answer:

○ C. The lines are perpendicular.

Step-by-step explanation:

In order for equations to be perpendicular, their rate of changes [slopes] must be OPPOSITE MULTIPLICATIVE INVERSES, which in this case is so:

− to +}

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MULTIPLICATIVE INVERSE [RECIPROCAL]

I am joyous to assist you at any time.

8 0

4 years ago

Read 2 more answers

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago