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never [62]
3 years ago
11

Can someone please help me

Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

x = 123°

Step-by-step explanation:

Since B and D are parallel lines, then

x and 123° are corresponding angles and congruent, thus

x = 123°

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Basically, the higher the price an item is the more you will be taking off of it if it is 10 percent off. For example, at $50, 10 percent off is $5, but at $55, it’s $5.50. There is more to take away, making the final price less than the original. Hope that make sense!
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What is the sum of the first ten terms of the sequence 4, -12, 36, -144 ...?
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7 0
3 years ago
Callie got 37 pieces of Halloween candy. Her brother got 42 pieces. She wants to estimate to find about how many pieces of candy
Vikki [24]

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Callie needs to hide both her and her brother's candy from him so that none is eaten/stolen.  Then count each stash separately.  Put the candies in groups of 10 to quickly establish that over 70 pieces were collected.  Callie should steal a stack from her brother's pile while he's not looking.  Just calmly shift one stack of ten candies to her side.  She should announce she got 47 pieces and her brother only 32.

Step-by-step explanation:

3 0
2 years ago
9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
Question 1 (1 point)<br> Divide using any method.<br> -3x3 + 4.x2 + 2x – 5)<br> (x - 2)
valkas [14]

Answer:Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

0

.

x

+

1

4

x

2

-

2

x

-

5

Divide the highest order term in the dividend

4

x

2

by the highest order term in divisor

x

.

4

x

x

+

1

4

x

2

-

2

x

-

5

Multiply the new quotient term by the divisor.

4

x

x

+

1

4

x

2

-

2

x

-

5

+

4

x

2

+

4

x

The expression needs to be subtracted from the dividend, so change all the signs in

4

x

2

+

4

x

4

x

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

4

x

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

Pull the next terms from the original dividend down into the current dividend.

4

x

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

-

5

Divide the highest order term in the dividend

−

6

x

by the highest order term in divisor

x

.

4

x

-

6

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

-

5

Multiply the new quotient term by the divisor.

4

x

-

6

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

-

5

-

6

x

-

6

The expression needs to be subtracted from the dividend, so change all the signs in

−

6

x

−

6

4

x

-

6

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

-

5

+

6

x

+

6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

4

x

-

6

x

+

1

4

x

2

-

2

x

-

5

-

4

x

2

-

4

x

-

6

x

-

5

+

6

x

+

6

+

1

The final answer is the quotient plus the remainder over the divisor.

4

x

−

6

+

1

x

+

1

Step-by-step explanation:

3 0
2 years ago
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