The second store offered the better buy at the price of $92.00.
What is better buy?
Better buy refers to the lowest price out of the prices offered by the three stores.
In order to determine the lowest price, the no discount price of the first store needs to be compared to the prices of two other stores, bearing that after-discount price is the pre-discount price multiplied by 1 minus the discount rate.
First store price=$95.00
Second store after-discount price=pre-tax discount price*(1-discount rate)
pre-discount price=$115
discount rate=20%
Second store after-discount price=$115*(1-20%)
Second store after-discount price=$92.00
Third store after-discount price=pre-tax discount price*(1-discount rate)
pre-discount price=$105
discount rate=10%
Third store after-discount price=$105*(1-10%)
Third store after-discount price=$94.50
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I will be able to answer this question, if it wasn't sideways
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
Answer:
just graph it mate
Step-by-step explanation:
The answer would be line segment.