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3 years ago

If the probability of an events is 2/7 what must be the probability of its compliments

Mathematics

1 answer:

monitta3 years ago

6 0

Answer:

The probability of its compliments = 0.7143 = 5/7

Step-by-step explanation:

The probability of an events = P= 2/7 = 0.2857

The probability of its compliments = 1-p = 1-0.2857 = 0.7143 = 5/7

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ivanzaharov [21]

Answer (assuming it can be in point-slope form):

$y + 8 = \frac{1}{3} (x+6)$

Step-by-step explanation:

With the given information, we can use the point-slope formula, $y-y_1 = m (x-x_1)$ , to write the equation of the line. Substitute values for the $m$ , $x_1$ , and $y_1$ in the formula to do so.

The $m$ represents the slope, so substitute $\frac{1}{3}$ in its place. The $x_1$ and $y_1$ represent the x and y values of one point the line intersects, so substitute -6 for $x_1$ and -8 for $y_1$ . This gives the following answer and equation (just make sure to convert the double negatives into positives:

$y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)$

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I'm not following. What's the question?

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4 years ago

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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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