It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.
<h3>How to illustrate the information?</h3>
It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.
1934 = 1000 + 900 + 30 + 4
Therefore the value of 9 will be:
= 30 × 3
Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.
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Answer:
20
Step-by-step explanation:
Use <u>PEMDAS</u>
P = parenthesis
E = Exponents
M = Multiplication*
D = Division*
A = Addition**
S = Subtraction**
*either can come first, it just depends which comes first in the equation.
**either can come first, it just depends which comes first in the equation.
<em>Step 1 : Write equation</em> 4( 9 × 2 ) ÷ ( 4 -1 ) - 4
<em>Step 2: Solve in parenthesis </em>4(18) ÷ (3) - 4
<em>Step 3: Solve multiplication </em> 72 ÷ 3 - 4
<em>Step 4: Solve division </em>24 - 4
<em>Step 5 : Solve subtraction</em> 20
Answer:
(2,8)
Step-by-step explanation:
Add them together to get rid of the y.
-6x = -4 - y
-7x = -22 + y
=
-13x = -26
Then solve for x.
-13x/-13 = -26/-13
x = 2
Now plug in the x value into either equation and solve for y.
-7(2) = -22 + y
-14 = -22 + y
-14 + 22 = -22 + 22 + y
8 = y
So...
x = 2
y = 8
(2,8)
Step-by-step explanation:
You are just replacing the 'n' with the number in the 'n box'.
So if this is the formula:
then:
B(-3)= 4-(-3/3)
B(-3)= 4-( -1)
B(-3)= 4+1
B(-3)= 5
B(0)= 4-(0/3)
B(0)= 4-0
B(0)= 4
B(3)= 4-(3/3)
B(3)= 4-1
B(3)= 3
You get imaginary roots for this equation.
x=4-5i
x=4+5i
