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aleksley [76]
4 years ago
8

Find the range and the interquartile range. 57,96,72,63,88

Mathematics
2 answers:
Over [174]4 years ago
7 0

The range is 39

The interquartile range is 32

Explanation:

The given data is 57,96,72,63,88

Let us arrange the data in ascending order.

Thus, we have,

57,63,72,88,96

We need to determine the range and interquartile range of the data.

Range:

The range of the data is the difference between the highest and the lowest value in the given data.

Highest value = 96

Lowest value = 57

Range = Highest value - Lowest value

           = 96 - 57

           = 39

Thus, the range of the data is 39

Interquartile range:

The interquartile range is the difference between the upper quartile and the lower quartile in the given data.

From, the given data, we have, 3 quartiles. They are Q_1 , Q_2 and Q_3

Q_2=72

Q_1=\frac{57+63}{2} =60

Q_3=\frac{88+96}{2} =92

Interquartile range = Q_3-Q_1

                               =  92-60

                               =  32

The interquartile range is 32

yanalaym [24]4 years ago
4 0

List the data set from least to greatest:

57, 63, 72, 88, 96

Range: Highest value - Lowest value = answer

Range: 96 - 57 = 39

(IQR) Interquartile Range: Upper quartile - Lower quartile = answer

(IQR) Interquartile range: 88.5 - 57.5 = 31

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