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3 years ago

Bridget reads 5 pages of her book per day 4 days per week for several weeks.

1 answer:

8 0

It would be w(5•4) because she reads 20 pages in one week. then you can multiply 20 by any number of weeks to get that number of pages in total.

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Suppose the number of free throws in a basketball game by one player are normally distributed with a standard deviation 0.97 fre

babunello [35]

Answer: 1.960

Step-by-step explanation:

The value of z we use to calculate a confidence interval with a ( $1-\alpha$ ) confidence level is a two-tailed test value i.e. represented by :-

$z_{\alpha/2}$

Given : The level of confidence: $1-\alpha=0.95$

Then, significance level : $\alpha: 1-0.95=0.05$

With the help of standard normal distribution table for z , we have

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.960$

Hence, the value of z should be used to calculate a confidence interval with a 95% confidence level =1.960

3 0

3 years ago

What are the coordinates of the midpoint of the line segment with end points J (-6, 3) and K (4, -2)

iVinArrow [24]

Answer:

(-1 , 1.5)

Step-by-step explanation:

7 0

3 years ago

Determine the product

astraxan [27]

= -10x^2 - 6xy + 6xz

hope it helps

6 0

3 years ago

Read 2 more answers

The sum of 5 consecutive integers is 100. What is the first number in this sequence?

yanalaym [24]

So we can call first number "n"

Then all five integers would be n, n+1, n+2, n+3, n+4

So sum of them would be 5n + 10 = 100

Now you can solve for n:

5n + 10 = 100

5n = 90

n = 18

Verify: 18 + 19 + 20 + 21 + 22 = 100. All good.

So answer is 18

5 0

3 years ago

The sum of the first 150 negative integers is represented using the expression What is the sum of the first 150 negative integer

Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

To know the answer, is convenient to replace some values of "n" in the sum $\sum_{(n=1)}^{150}[-1-(n-1)]$ .

The result would appear after adding up every value of the expression $\sum_{(n=1)}^{150}[-1-(n-1)]$ when n=1,2,3.....,150.
When n=1, the expression takes the value of (-1): $[-1-(1-1)]= (-1)-0=-1$ .
When n=2, the expression takes the value of (-2): $[-1-(2-1)]=-1-1=-2$ .
Following this way, for every n, we will obtain -n, then, the sum will be: $-1-2-3-4-5-6-...-150$ . This sum can actually be expressed as $\sum_{n=1}^{150}(-n)$ , which is the result of solving the initial expression of the sum $-1-(n-1)=-1-n+1=-n$ .
Finally, the sum of n=-1 to n=-150 equals -11,325.

7 0

3 years ago

Read 2 more answers