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3 years ago

10

How to solve this equation?

2 answers:

bezimeni [28]3 years ago

8 0

$\bf log_2(x-2)-log_2(5)=1\\\\
-----------------------------\\\\
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\qquad thus\\\\
-----------------------------\\\\
log_2\left( \cfrac{x-2}{5} \right)=1\\\\
-----------------------------\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\
2^{\cfrac{}{}log_2\left( \frac{x-2}{5} \right)}=2^1\implies \cfrac{x-2}{5}=2^1
\\\\\\
\cfrac{x-2}{5}=2\implies x-2=10\implies x=12$

lilavasa [31]3 years ago

7 0

I solved it on your other posting of it. x = 12
All of the steps are there

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Answer:

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Step-by-step explanation:

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3 years ago

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34kurt

Answer:

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Step-by-step explanation:

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dusya [7]

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Answer:

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Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

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we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

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(x,y) = (7,-13)

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so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

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we can solve these two equation using the elimination method, by simply adding the two equations

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------------------------------

$\quad\quad 98a=-26$

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Now we can plug this value of a in any of the two equations.

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$y=-\dfrac{13}{49}x^2$

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This our equation of the arch!

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