How to solve this equation?

Mathematics

2 answers:

bezimeni [28]3 years ago

8 0

$\bf log_2(x-2)-log_2(5)=1\\\\
-----------------------------\\\\
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\qquad thus\\\\
-----------------------------\\\\
log_2\left( \cfrac{x-2}{5} \right)=1\\\\
-----------------------------\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\
2^{\cfrac{}{}log_2\left( \frac{x-2}{5} \right)}=2^1\implies \cfrac{x-2}{5}=2^1
\\\\\\
\cfrac{x-2}{5}=2\implies x-2=10\implies x=12$

lilavasa [31]3 years ago

7 0

I solved it on your other posting of it. x = 12
All of the steps are there

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Easy algebra question below first correct answer gets brainliest

kirill [66]

Given:

The right angle triangle with legs 4 units and 7 units.

To find:

The length of hypotenuse.

Solution:

Pythagoras theorem: In a right angle triangle,

$Hypotenuse^2=Base^2+Perpendicular^2$

Let x be the length of the hypotenuse.

Using the Pythagoras theorem for the given triangle, we get

$x^2=4^2+7^2$

$x^2=16+49$

$x^2=65$

Taking square root on both sides, we get

$x=\sqrt{65}$ [∵Side length cannot be negative]

$x\approx 8.06$

Therefore, the length of the missing side for the given right angle triangle is 8.06 units.

3 0

3 years ago

Pls help me answer this

igor_vitrenko [27]

Answer: 30 cm

Step-by-step explanation:

The volume of the composite solid is 17000 cm³. To find h, we must first subtract the volume of the half cylinder from the composite volume.

From the figure, AE = MK, and so the radius of the half cylinder is 10cm. The volume of the half cylinder is thus $\frac{1}{2}$ the volume of a cylinder. The volume of a cylinder is πr²h. So a half cylinder is 1/2 πr²h. This gives us a volume of $\frac{1}{2} (\frac{22}{7})(10 cm)^2(28 cm) = 4400 cm^3$ .

Thus, the volume of the right prism is 17000cm³ - 4400cm³ = 12600cm³. Consider the cross-section ABKJ. If we multiply this by AE, we'll have the volume of the right prism.

The ABKJ is a trapezoid so it's area is $\frac{1}{2}(AJ + BK) \cdot AB$ . Thus the volume of the right prism is $\frac{1}{2}(AJ + BK) \cdot AB \cdot AE$ . This gives us $\frac{1}{2}(28 + 14) \cdot h \cdot 20 = 12600$ , and thus h = 30 cm.