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3 years ago

Bill wants to be at school at 8:05 A.M. It takes him 20 minutes to walk to school. At what time should bill leave his house

Mathematics

2 answers:

LenaWriter [7]3 years ago

7 0

.... Bill should leave his house at 7:45 am

sukhopar [10]3 years ago

4 0

Total duration: 20 mins
8.05 am , count back 5 mins = 8 am

20 mins - 5 mins = 15 mins

8 am, count back 15 mins = 7.45am

He needs to leave the house at 7.45am

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This exercise uses, the population growth model

timofeeve [1]

P is equal to 8700% for population x time in hours.

<h3>What is population growth model?</h3>

P is equal to 8700% for population x time in hours. 2Ae%5E%28kx%29

K's model must be solved. ln%28p%29=ln%288700%29%

2Bkx%2Aln%28e%

29\skx%

2A1=ln%28p%29-ln%288700%

29\sk=%281%

2Fx%29%

28ln%28p%29-ln%288700%29%29

Replace the point (1,10000).

k=%281%

2F1%29%

28ln%2810000%

29-ln%288700%

29%

29\sk=ln%2810000%

29-ln%288700%

29 k=0.13926, which you might only desire to three or maybe even two significant figures.

You may just enter 10000% if you want p after two hours.

And it SHOULD be the same as 8700% (2810000%2F8700%).

Just give it a shot and see, 2Ae%5E%280.139%2A2%29. More particular, the model is highlighted by p=8700%. 2Ae%5E%280.139% 2Ax%29% 29.

Determine how long to double x.

Take the logs on both sides, then find x.

To put it more simply, start with this form: 2=1%2Ae%5E%280.13926%2Ax%29

To learn more about population growth model refer to:

brainly.com/question/25896797

#SPJ4

5 0

1 year ago

Pls help due asap! <br> Pls SHOW WORKINGS

sladkih [1.3K]

Answer:

$m\angle 1=95^{\circ}$

Step-by-step explanation:

If we drew an auxiliary line parallel to line $p$ and line $q$ that intersects the vertex of $\angle 1$ , we would form three angles, one of them being

The largest of these angles corresponds with the angle marked as $148^{\circ}$ .

The angle on the bottom right corresponds with the angle next to the one marked as $63^{\circ}$ . Therefore, its measure is $180-63=117^{\circ}$ .

Since there are $360^{\circ}$ in a circle, we can now write the following equation:

$m\angle 1+117+148=360,\\m\angle 1=\fbox{$95^{\circ}\checkmark$}$ .

3 0

3 years ago

Read 2 more answers

Which of the following situations best represents causation?

miss Akunina [59]

Well, causation is the relationship between cause and effect. I think the answer is A. If it is raining, then there are clouds in the sky because of the fact that the cause is the clouds and the effect is the rain from the clouds. Hope this helped!

8 0

3 years ago

Convert the angle 45°29'13" to decimal degrees and round to the nearest hundredth of a degree

Bad White [126]

Add this. $45+ \frac{29}{60}+ \frac{13}{3600}$

4 0

3 years ago

Read 2 more answers

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

3 years ago